(b^2-7b-60)/(b+3)

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Solution for (b^2-7b-60)/(b+3) equation: 


D( b )

b+3 = 0

b+3 = 0

b+3 = 0

b+3 = 0 // - 3

b = -3

b in (-oo:-3) U (-3:+oo)

(b^2-(7*b)-60)/(b+3) = 0

(b^2-7*b-60)/(b+3) = 0

b^2-7*b-60 = 0

b^2-7*b-60 = 0

DELTA = (-7)^2-(-60*1*4)

DELTA = 289

DELTA > 0

b = (289^(1/2)+7)/(1*2) or b = (7-289^(1/2))/(1*2)

b = 12 or b = -5

(b+5)*(b-12) = 0

((b+5)*(b-12))/(b+3) = 0

( b+5 )

b+5 = 0 // - 5

b = -5

( b-12 )

b-12 = 0 // + 12

b = 12

b in { -5, 12 }

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